7x^2-8=-49x-8

Solution for 7x^2-8=-49x-8 equation:

7x^2-8=-49x-8

We move all terms to the left:

7x^2-8-(-49x-8)=0

We get rid of parentheses

7x^2+49x+8-8=0

We add all the numbers together, and all the variables

7x^2+49x=0

a = 7; b = 49; c = 0;
Δ = b2-4ac
Δ = 492-4·7·0
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2401}=49$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(49)-49}{2*7}=\frac{-98}{14}
=-7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(49)+49}{2*7}=\frac{0}{14}
=0
$